Solve (({left(1/3right)}^-2)-({left(1/9right)}^-2))div3^-2

$$(( { \left( \frac{ 1 }{ 3 } \right) }^{ -2 } )-( { \left( \frac{ 1 }{ 9 } \right) }^{ -2 } )) \div { 3 }^{ -2 }$$

Evaluate

$$-648$$

Solution Steps

Calculate \frac{1}{3} to the power of -2 and get 9.

$$\frac{9-\left(\frac{1}{9}\right)^{-2}}{3^{-2}}$$

Calculate \frac{1}{9} to the power of -2 and get 81.

$$\frac{9-81}{3^{-2}}$$

Subtract 81 from 9 to get -72.

$$\frac{-72}{3^{-2}}$$

Calculate 3 to the power of -2 and get \frac{1}{9}.

$$\frac{-72}{\frac{1}{9}}$$

Divide -72 by \frac{1}{9} by multiplying -72 by the reciprocal of \frac{1}{9}.

$$-72\times 9$$

Multiply -72 and 9 to get -648.

$$-648$$

Factor

$$-648$$