Solve ((18/1div20/3)+59/4)-5/2

$$(( \frac{ 18 }{ 1 } \div \frac{ 20 }{ 3 } )+ \frac{ 59 }{ 4 } )- \frac{ 5 }{ 2 }$$

Evaluate

$$\frac{299}{20}=14.95$$

Solution Steps

Divide \frac{18}{1} by \frac{20}{3} by multiplying \frac{18}{1} by the reciprocal of \frac{20}{3}.

$$\frac{18\times 3}{20}+\frac{59}{4}-\frac{5}{2}$$

Multiply 18 and 3 to get 54.

$$\frac{54}{20}+\frac{59}{4}-\frac{5}{2}$$

Reduce the fraction \frac{54}{20} to lowest terms by extracting and canceling out 2.

$$\frac{27}{10}+\frac{59}{4}-\frac{5}{2}$$

Least common multiple of 10 and 4 is 20. Convert \frac{27}{10} and \frac{59}{4} to fractions with denominator 20.

$$\frac{54}{20}+\frac{295}{20}-\frac{5}{2}$$

Since \frac{54}{20} and \frac{295}{20} have the same denominator, add them by adding their numerators.

$$\frac{54+295}{20}-\frac{5}{2}$$

Add 54 and 295 to get 349.

$$\frac{349}{20}-\frac{5}{2}$$

Least common multiple of 20 and 2 is 20. Convert \frac{349}{20} and \frac{5}{2} to fractions with denominator 20.

$$\frac{349}{20}-\frac{50}{20}$$

Since \frac{349}{20} and \frac{50}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{349-50}{20}$$

Subtract 50 from 349 to get 299.

$$\frac{299}{20}$$

Factor

$$\frac{13 \cdot 23}{2 ^ {2} \cdot 5} = 14\frac{19}{20} = 14.95$$