Solve for y
y=6
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y^{2}-10y+25-y^{2}=-35
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(y-5\right)^{2}.
-10y+25=-35
Combine y^{2} and -y^{2} to get 0.
-10y=-35-25
Subtract 25 from both sides.
-10y=-60
Subtract 25 from -35 to get -60.
y=\frac{-60}{-10}
Divide both sides by -10.
y=6
Divide -60 by -10 to get 6.
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