Solve for x
x=\left(y-4\right)^{2}
Solve for y (complex solution)
y=-\sqrt{x}+4
y=\sqrt{x}+4
Solve for y
y=-\sqrt{x}+4
y=\sqrt{x}+4\text{, }x\geq 0
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y^{2}-8y+16=x
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(y-4\right)^{2}.
x=y^{2}-8y+16
Swap sides so that all variable terms are on the left hand side.
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