Solve (y-2)(y-1)(y+1)

$$( y - 2 ) ( y - 1 ) ( y + 1 )$$

Evaluate

$$\left(y-2\right)\left(y^{2}-1\right)$$

Solution Steps

Apply the distributive property by multiplying each term of y-2 by each term of y-1.

$$\left(y^{2}-y-2y+2\right)\left(y+1\right)$$

Combine -y and -2y to get -3y.

$$\left(y^{2}-3y+2\right)\left(y+1\right)$$

Apply the distributive property by multiplying each term of y^{2}-3y+2 by each term of y+1.

$$y^{3}+y^{2}-3y^{2}-3y+2y+2$$

Combine y^{2} and -3y^{2} to get -2y^{2}.

$$y^{3}-2y^{2}-3y+2y+2$$

Combine -3y and 2y to get -y.

$$y^{3}-2y^{2}-y+2$$

Expand

$$y^{3}-2y^{2}-y+2$$

Solution Steps

Apply the distributive property by multiplying each term of y-2 by each term of y-1.

$$\left(y^{2}-y-2y+2\right)\left(y+1\right)$$

Combine -y and -2y to get -3y.

$$\left(y^{2}-3y+2\right)\left(y+1\right)$$

Apply the distributive property by multiplying each term of y^{2}-3y+2 by each term of y+1.

$$y^{3}+y^{2}-3y^{2}-3y+2y+2$$

Combine y^{2} and -3y^{2} to get -2y^{2}.

$$y^{3}-2y^{2}-3y+2y+2$$

Combine -3y and 2y to get -y.

$$y^{3}-2y^{2}-y+2$$