Solve (y^3-5y^2-6y)div(y^2-1)*(2y^2+y-3)

$$( y ^ { 3 } - 5 y ^ { 2 } - 6 y ) \div ( y ^ { 2 } - 1 ) \times ( 2 y ^ { 2 } + y - 3 )$$

Evaluate

$$y\left(y-6\right)\left(2y+3\right)$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{y^{3}-5y^{2}-6y}{y^{2}-1}.

$$\frac{y\left(y-6\right)\left(y+1\right)}{\left(y-1\right)\left(y+1\right)}\left(2y^{2}+y-3\right)$$

Cancel out y+1 in both numerator and denominator.

$$\frac{y\left(y-6\right)}{y-1}\left(2y^{2}+y-3\right)$$

Express \frac{y\left(y-6\right)}{y-1}\left(2y^{2}+y-3\right) as a single fraction.

$$\frac{y\left(y-6\right)\left(2y^{2}+y-3\right)}{y-1}$$

Factor the expressions that are not already factored.

$$\frac{y\left(y-6\right)\left(y-1\right)\left(2y+3\right)}{y-1}$$

Cancel out y-1 in both numerator and denominator.

$$y\left(y-6\right)\left(2y+3\right)$$

Expand the expression.

$$2y^{3}-9y^{2}-18y$$

Expand

$$2y^{3}-9y^{2}-18y$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{y^{3}-5y^{2}-6y}{y^{2}-1}.

$$\frac{y\left(y-6\right)\left(y+1\right)}{\left(y-1\right)\left(y+1\right)}\left(2y^{2}+y-3\right)$$

Cancel out y+1 in both numerator and denominator.

$$\frac{y\left(y-6\right)}{y-1}\left(2y^{2}+y-3\right)$$

Express \frac{y\left(y-6\right)}{y-1}\left(2y^{2}+y-3\right) as a single fraction.

$$\frac{y\left(y-6\right)\left(2y^{2}+y-3\right)}{y-1}$$

Factor the expressions that are not already factored.

$$\frac{y\left(y-6\right)\left(y-1\right)\left(2y+3\right)}{y-1}$$

Cancel out y-1 in both numerator and denominator.

$$y\left(y-6\right)\left(2y+3\right)$$

Expand the expression.

$$2y^{3}-9y^{2}-18y$$