Solve (y+2)i+(x-3)=9i-5

$$( y + 2 ) i + ( x - 3 ) = 9 i - 5$$

Solve for y

$$y=ix+\left(7+2i\right)$$

Steps for Solving Linear Equation

Use the distributive property to multiply y+2 by i.

$$iy+2i+x-3=9i-5$$

Subtract 2i from both sides.

$$iy+x-3=9i-5-2i$$

Do the additions in 9i-5-2i.

$$iy+x-3=-5+7i$$

Subtract x from both sides.

$$iy-3=-5+7i-x$$

Add 3 to both sides.

$$iy=-5+7i-x+3$$

Do the additions in -5+7i+3.

$$iy=-x-2+7i$$

The equation is in standard form.

$$iy=-2+7i-x$$

Divide both sides by i.

$$\frac{iy}{i}=\frac{-2+7i-x}{i}$$

Dividing by i undoes the multiplication by i.

$$y=\frac{-2+7i-x}{i}$$

Divide -x+\left(-2+7i\right) by i.

$$y=ix+\left(7+2i\right)$$

Solve for x

$$x=-2+7i-iy$$