Solve (x-y+3)(x-y-4)

$$( x - y + 3 ) ( x - y - 4 )$$

Evaluate

$$\left(x-y-4\right)\left(x-y+3\right)$$

Solution Steps

Apply the distributive property by multiplying each term of x-y+3 by each term of x-y-4.

$$x^{2}-xy-4x-yx+y^{2}+4y+3x-3y-12$$

Combine -xy and -yx to get -2xy.

$$x^{2}-2xy-4x+y^{2}+4y+3x-3y-12$$

Combine -4x and 3x to get -x.

$$x^{2}-2xy-x+y^{2}+4y-3y-12$$

Combine 4y and -3y to get y.

$$x^{2}-2xy-x+y^{2}+y-12$$

Expand

$$x^{2}-2xy-x+y^{2}+y-12$$

Solution Steps

Apply the distributive property by multiplying each term of x-y+3 by each term of x-y-4.

$$x^{2}-xy-4x-yx+y^{2}+4y+3x-3y-12$$

Combine -xy and -yx to get -2xy.

$$x^{2}-2xy-4x+y^{2}+4y+3x-3y-12$$

Combine -4x and 3x to get -x.

$$x^{2}-2xy-x+y^{2}+4y-3y-12$$

Combine 4y and -3y to get y.

$$x^{2}-2xy-x+y^{2}+y-12$$