Solve (x-5)^2=x^2-25

$$( x - 5 ) ^ { 2 } = x ^ { 2 } - 25$$

Solve for x

$$x=5$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-5\right)^{2}.

$$x^{2}-10x+25=x^{2}-25$$

Subtract x^{2} from both sides.

$$x^{2}-10x+25-x^{2}=-25$$

Combine x^{2} and -x^{2} to get 0.

$$-10x+25=-25$$

Subtract 25 from both sides.

$$-10x=-25-25$$

Subtract 25 from -25 to get -50.

$$-10x=-50$$

Divide both sides by -10.

$$x=\frac{-50}{-10}$$

Divide -50 by -10 to get 5.

$$x=5$$