Solve (x-3)(x+2)=x(x+1)-3(x+2)+3

$$( x - 3 ) ( x + 2 ) = x ( x + 1 ) - 3 ( x + 2 ) + 3$$

Solve for x

$$x=3$$

Steps for Solving Linear Equation

Use the distributive property to multiply x-3 by x+2 and combine like terms.

$$x^{2}-x-6=x\left(x+1\right)-3\left(x+2\right)+3$$

Use the distributive property to multiply x by x+1.

$$x^{2}-x-6=x^{2}+x-3\left(x+2\right)+3$$

Use the distributive property to multiply -3 by x+2.

$$x^{2}-x-6=x^{2}+x-3x-6+3$$

Combine x and -3x to get -2x.

$$x^{2}-x-6=x^{2}-2x-6+3$$

Add -6 and 3 to get -3.

$$x^{2}-x-6=x^{2}-2x-3$$

Subtract x^{2} from both sides.

$$x^{2}-x-6-x^{2}=-2x-3$$

Combine x^{2} and -x^{2} to get 0.

$$-x-6=-2x-3$$

Add 2x to both sides.

$$-x-6+2x=-3$$

Combine -x and 2x to get x.

$$x-6=-3$$

Add 6 to both sides.

$$x=-3+6$$

Add -3 and 6 to get 3.

$$x=3$$