Solve (x-3)(4x+2)=4x^2+3

$$( x - 3 ) ( 4 x + 2 ) = 4 x ^ { 2 } + 3$$

Solve for x

$$x=-\frac{9}{10}=-0.9$$

Steps for Solving Linear Equation

Use the distributive property to multiply x-3 by 4x+2 and combine like terms.

$$4x^{2}-10x-6=4x^{2}+3$$

Subtract 4x^{2} from both sides.

$$4x^{2}-10x-6-4x^{2}=3$$

Combine 4x^{2} and -4x^{2} to get 0.

$$-10x-6=3$$

Add 6 to both sides.

$$-10x=3+6$$

Add 3 and 6 to get 9.

$$-10x=9$$

Divide both sides by -10.

$$x=\frac{9}{-10}$$

Fraction \frac{9}{-10} can be rewritten as -\frac{9}{10} by extracting the negative sign.

$$x=-\frac{9}{10}$$