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x^{3}-9x^{2}+27x-27-\left(x+3\right)
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-3\right)^{3}.
x^{3}-9x^{2}+27x-27-x-3
To find the opposite of x+3, find the opposite of each term.
x^{3}-9x^{2}+26x-27-3
Combine 27x and -x to get 26x.
x^{3}-9x^{2}+26x-30
Subtract 3 from -27 to get -30.
x^{3}-9x^{2}+27x-27-\left(x+3\right)
Use binomial theorem \left(a-b\right)^{3}=a^{3}-3a^{2}b+3ab^{2}-b^{3} to expand \left(x-3\right)^{3}.
x^{3}-9x^{2}+27x-27-x-3
To find the opposite of x+3, find the opposite of each term.
x^{3}-9x^{2}+26x-27-3
Combine 27x and -x to get 26x.
x^{3}-9x^{2}+26x-30
Subtract 3 from -27 to get -30.