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Solve for x (complex solution)
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x^{2}-6x+9=y+2
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-3\right)^{2}.
y+2=x^{2}-6x+9
Swap sides so that all variable terms are on the left hand side.
y=x^{2}-6x+9-2
Subtract 2 from both sides.
y=x^{2}-6x+7
Subtract 2 from 9 to get 7.