Solve (x-2)(x-2)=x^2

$$( x - 2 ) ( x - 2 ) = x ^ { 2 }$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Multiply x-2 and x-2 to get \left(x-2\right)^{2}.

$$\left(x-2\right)^{2}=x^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.

$$x^{2}-4x+4=x^{2}$$

Subtract x^{2} from both sides.

$$x^{2}-4x+4-x^{2}=0$$

Combine x^{2} and -x^{2} to get 0.

$$-4x+4=0$$

Subtract 4 from both sides. Anything subtracted from zero gives its negation.

$$-4x=-4$$

Divide both sides by -4.

$$x=\frac{-4}{-4}$$

Divide -4 by -4 to get 1.

$$x=1$$