Solve for x
x=-2
x=6
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x^{2}+4x-12=8x
Use the distributive property to multiply x-2 by x+6 and combine like terms.
x^{2}+4x-12-8x=0
Subtract 8x from both sides.
x^{2}-4x-12=0
Combine 4x and -8x to get -4x.
a+b=-4 ab=-12
To solve the equation, factor x^{2}-4x-12 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.
1,-12 2,-6 3,-4
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -12.
1-12=-11 2-6=-4 3-4=-1
Calculate the sum for each pair.
a=-6 b=2
The solution is the pair that gives sum -4.
\left(x-6\right)\left(x+2\right)
Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.
x=6 x=-2
To find equation solutions, solve x-6=0 and x+2=0.
x^{2}+4x-12=8x
Use the distributive property to multiply x-2 by x+6 and combine like terms.
x^{2}+4x-12-8x=0
Subtract 8x from both sides.
x^{2}-4x-12=0
Combine 4x and -8x to get -4x.
a+b=-4 ab=1\left(-12\right)=-12
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx-12. To find a and b, set up a system to be solved.
1,-12 2,-6 3,-4
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -12.
1-12=-11 2-6=-4 3-4=-1
Calculate the sum for each pair.
a=-6 b=2
The solution is the pair that gives sum -4.
\left(x^{2}-6x\right)+\left(2x-12\right)
Rewrite x^{2}-4x-12 as \left(x^{2}-6x\right)+\left(2x-12\right).
x\left(x-6\right)+2\left(x-6\right)
Factor out x in the first and 2 in the second group.
\left(x-6\right)\left(x+2\right)
Factor out common term x-6 by using distributive property.
x=6 x=-2
To find equation solutions, solve x-6=0 and x+2=0.
x^{2}+4x-12=8x
Use the distributive property to multiply x-2 by x+6 and combine like terms.
x^{2}+4x-12-8x=0
Subtract 8x from both sides.
x^{2}-4x-12=0
Combine 4x and -8x to get -4x.
x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\left(-12\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -4 for b, and -12 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-4\right)±\sqrt{16-4\left(-12\right)}}{2}
Square -4.
x=\frac{-\left(-4\right)±\sqrt{16+48}}{2}
Multiply -4 times -12.
x=\frac{-\left(-4\right)±\sqrt{64}}{2}
Add 16 to 48.
x=\frac{-\left(-4\right)±8}{2}
Take the square root of 64.
x=\frac{4±8}{2}
The opposite of -4 is 4.
x=\frac{12}{2}
Now solve the equation x=\frac{4±8}{2} when ± is plus. Add 4 to 8.
x=6
Divide 12 by 2.
x=-\frac{4}{2}
Now solve the equation x=\frac{4±8}{2} when ± is minus. Subtract 8 from 4.
x=-2
Divide -4 by 2.
x=6 x=-2
The equation is now solved.
x^{2}+4x-12=8x
Use the distributive property to multiply x-2 by x+6 and combine like terms.
x^{2}+4x-12-8x=0
Subtract 8x from both sides.
x^{2}-4x-12=0
Combine 4x and -8x to get -4x.
x^{2}-4x=12
Add 12 to both sides. Anything plus zero gives itself.
x^{2}-4x+\left(-2\right)^{2}=12+\left(-2\right)^{2}
Divide -4, the coefficient of the x term, by 2 to get -2. Then add the square of -2 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-4x+4=12+4
Square -2.
x^{2}-4x+4=16
Add 12 to 4.
\left(x-2\right)^{2}=16
Factor x^{2}-4x+4. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-2\right)^{2}}=\sqrt{16}
Take the square root of both sides of the equation.
x-2=4 x-2=-4
Simplify.
x=6 x=-2
Add 2 to both sides of the equation.
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Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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