Solve for x
x=12
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x^{2}-4x+4-x^{2}=-44
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
-4x+4=-44
Combine x^{2} and -x^{2} to get 0.
-4x=-44-4
Subtract 4 from both sides.
-4x=-48
Subtract 4 from -44 to get -48.
x=\frac{-48}{-4}
Divide both sides by -4.
x=12
Divide -48 by -4 to get 12.
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