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x^{2}-4x+4+5\left(2-x\right)=\left(x+1\right)\left(x-1\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-2\right)^{2}.
x^{2}-4x+4+10-5x=\left(x+1\right)\left(x-1\right)
Use the distributive property to multiply 5 by 2-x.
x^{2}-4x+14-5x=\left(x+1\right)\left(x-1\right)
Add 4 and 10 to get 14.
x^{2}-9x+14=\left(x+1\right)\left(x-1\right)
Combine -4x and -5x to get -9x.
x^{2}-9x+14=x^{2}-1
Consider \left(x+1\right)\left(x-1\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 1.
x^{2}-9x+14-x^{2}=-1
Subtract x^{2} from both sides.
-9x+14=-1
Combine x^{2} and -x^{2} to get 0.
-9x=-1-14
Subtract 14 from both sides.
-9x=-15
Subtract 14 from -1 to get -15.
x=\frac{-15}{-9}
Divide both sides by -9.
x=\frac{5}{3}
Reduce the fraction \frac{-15}{-9} to lowest terms by extracting and canceling out -3.