Solve for x (complex solution)
x=2-4i
x=2+4i
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\left(x-2\right)^{2}=-16
Subtracting 16 from itself leaves 0.
x-2=4i x-2=-4i
Take the square root of both sides of the equation.
x-2-\left(-2\right)=4i-\left(-2\right) x-2-\left(-2\right)=-4i-\left(-2\right)
Add 2 to both sides of the equation.
x=4i-\left(-2\right) x=-4i-\left(-2\right)
Subtracting -2 from itself leaves 0.
x=2+4i
Subtract -2 from 4i.
x=2-4i
Subtract -2 from -4i.
x=2+4i x=2-4i
The equation is now solved.
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