Solve for x
x=22
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x^{2}-20x+100-x^{2}=-340
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-10\right)^{2}.
-20x+100=-340
Combine x^{2} and -x^{2} to get 0.
-20x=-340-100
Subtract 100 from both sides.
-20x=-440
Subtract 100 from -340 to get -440.
x=\frac{-440}{-20}
Divide both sides by -20.
x=22
Divide -440 by -20 to get 22.
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