Solve (x-1)-3leq7x+4

$$( x - 1 ) - 3 \leq 7 x + 4$$

Solve for x

$$x\geq -\frac{4}{3}$$

Solution Steps

Subtract 3 from -1 to get -4.

$$x-4\leq 7x+4$$

Subtract 7x from both sides.

$$x-4-7x\leq 4$$

Combine x and -7x to get -6x.

$$-6x-4\leq 4$$

Add 4 to both sides.

$$-6x\leq 4+4$$

Add 4 and 4 to get 8.

$$-6x\leq 8$$

Divide both sides by -6. Since -6 is negative, the inequality direction is changed.

$$x\geq \frac{8}{-6}$$

Reduce the fraction \frac{8}{-6} to lowest terms by extracting and canceling out 2.

$$x\geq -\frac{4}{3}$$