Solve (x-1)^2-x^2=5

$$( x - 1 ) ^ { 2 } - x ^ { 2 } = 5$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.

$$x^{2}-2x+1-x^{2}=5$$

Combine x^{2} and -x^{2} to get 0.

$$-2x+1=5$$

Subtract 1 from both sides.

$$-2x=5-1$$

Subtract 1 from 5 to get 4.

$$-2x=4$$

Divide both sides by -2.

$$x=\frac{4}{-2}$$

Divide 4 by -2 to get -2.

$$x=-2$$