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x^{2}-2x+1=\left(x-7\right)\left(x+7\right)
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-1\right)^{2}.
x^{2}-2x+1=x^{2}-49
Consider \left(x-7\right)\left(x+7\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 7.
x^{2}-2x+1-x^{2}=-49
Subtract x^{2} from both sides.
-2x+1=-49
Combine x^{2} and -x^{2} to get 0.
-2x=-49-1
Subtract 1 from both sides.
-2x=-50
Subtract 1 from -49 to get -50.
x=\frac{-50}{-2}
Divide both sides by -2.
x=25
Divide -50 by -2 to get 25.