Solve (x-2xy-y^2/x)

$$( x - \frac { 2 x y - y ^ { 2 } } { x } )$$

Evaluate

$$\frac{\left(x-y\right)^{2}}{x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply x times \frac{x}{x}.

$$\frac{xx}{x}-\frac{2xy-y^{2}}{x}$$

Since \frac{xx}{x} and \frac{2xy-y^{2}}{x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{xx-\left(2xy-y^{2}\right)}{x}$$

Do the multiplications in xx-\left(2xy-y^{2}\right).

$$\frac{x^{2}-2xy+y^{2}}{x}$$

Expand

$$\frac{y^{2}}{x}+x-2y$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply x times \frac{x}{x}.

$$\frac{xx}{x}-\frac{2xy-y^{2}}{x}$$

Since \frac{xx}{x} and \frac{2xy-y^{2}}{x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{xx-\left(2xy-y^{2}\right)}{x}$$

Do the multiplications in xx-\left(2xy-y^{2}\right).

$$\frac{x^{2}-2xy+y^{2}}{x}$$