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x^{2}+100=\left(x+5\right)^{2}
Calculate 10 to the power of 2 and get 100.
x^{2}+100=x^{2}+10x+25
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+5\right)^{2}.
x^{2}+100-x^{2}=10x+25
Subtract x^{2} from both sides.
100=10x+25
Combine x^{2} and -x^{2} to get 0.
10x+25=100
Swap sides so that all variable terms are on the left hand side.
10x=100-25
Subtract 25 from both sides.
10x=75
Subtract 25 from 100 to get 75.
x=\frac{75}{10}
Divide both sides by 10.
x=\frac{15}{2}
Reduce the fraction \frac{75}{10} to lowest terms by extracting and canceling out 5.