Solve (x)=sqrt{x+5}

$$( x ) = \sqrt { x + 5 }$$

Solve for x

$$x = \frac{\sqrt{21} + 1}{2} \approx 2.791287847$$

Solution Steps

Square both sides of the equation.

$$x^{2}=\left(\sqrt{x+5}\right)^{2}$$

Calculate \sqrt{x+5} to the power of 2 and get x+5.

$$x^{2}=x+5$$

Subtract x from both sides.

$$x^{2}-x=5$$

Subtract 5 from both sides.

$$x^{2}-x-5=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -1 for b, and -5 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-1\right)±\sqrt{1-4\left(-5\right)}}{2}$$

Multiply -4 times -5.

$$x=\frac{-\left(-1\right)±\sqrt{1+20}}{2}$$

Add 1 to 20.

$$x=\frac{-\left(-1\right)±\sqrt{21}}{2}$$

The opposite of -1 is 1.

$$x=\frac{1±\sqrt{21}}{2}$$

Now solve the equation x=\frac{1±\sqrt{21}}{2} when ± is plus. Add 1 to \sqrt{21}.

$$x=\frac{\sqrt{21}+1}{2}$$

Now solve the equation x=\frac{1±\sqrt{21}}{2} when ± is minus. Subtract \sqrt{21} from 1.

$$x=\frac{1-\sqrt{21}}{2}$$

The equation is now solved.

$$x=\frac{\sqrt{21}+1}{2} x=\frac{1-\sqrt{21}}{2}$$

Substitute \frac{\sqrt{21}+1}{2} for x in the equation x=\sqrt{x+5}.

$$\frac{\sqrt{21}+1}{2}=\sqrt{\frac{\sqrt{21}+1}{2}+5}$$

Simplify. The value x=\frac{\sqrt{21}+1}{2} satisfies the equation.

$$\frac{1}{2}\times 21^{\frac{1}{2}}+\frac{1}{2}=\frac{1}{2}+\frac{1}{2}\times 21^{\frac{1}{2}}$$

Substitute \frac{1-\sqrt{21}}{2} for x in the equation x=\sqrt{x+5}.

$$\frac{1-\sqrt{21}}{2}=\sqrt{\frac{1-\sqrt{21}}{2}+5}$$

Simplify. The value x=\frac{1-\sqrt{21}}{2} does not satisfy the equation because the left and the right hand side have opposite signs.

$$\frac{1}{2}-\frac{1}{2}\times 21^{\frac{1}{2}}=-\left(\frac{1}{2}-\frac{1}{2}\times 21^{\frac{1}{2}}\right)$$

Equation x=\sqrt{x+5} has a unique solution.

$$x=\frac{\sqrt{21}+1}{2}$$