Solve (x)=x^3/x^2+4

$$( x ) = \frac { x ^ { 3 } } { x ^ { 2 } + 4 }$$

Solve for x

$$x=0$$

Steps for Solving Linear Equation

Subtract \frac{x^{3}}{x^{2}+4} from both sides.

$$x-\frac{x^{3}}{x^{2}+4}=0$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x times \frac{x^{2}+4}{x^{2}+4}.

$$\frac{x\left(x^{2}+4\right)}{x^{2}+4}-\frac{x^{3}}{x^{2}+4}=0$$

Since \frac{x\left(x^{2}+4\right)}{x^{2}+4} and \frac{x^{3}}{x^{2}+4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{x\left(x^{2}+4\right)-x^{3}}{x^{2}+4}=0$$

Do the multiplications in x\left(x^{2}+4\right)-x^{3}.

$$\frac{x^{3}+4x-x^{3}}{x^{2}+4}=0$$

Combine like terms in x^{3}+4x-x^{3}.

$$\frac{4x}{x^{2}+4}=0$$

Multiply both sides of the equation by x^{2}+4.

$$4x=0$$

Product of two numbers is equal to 0 if at least one of them is 0. Since 4 is not equal to 0, x must be equal to 0.

$$x=0$$