Solve (x^3y)^-1=

$$( x ^ { 3 } y ) ^ { - 1 } =$$

Evaluate

$$\frac{1}{yx^{3}}$$

Solution Steps

Use the rules of exponents to simplify the expression.

$$\frac{1}{x^{3}y^{1}}$$

To raise the product of two or more numbers to a power, raise each number to the power and take their product.

$$\frac{1}{x^{3}}\times \frac{1}{y^{1}}$$

To raise a power to another power, multiply the exponents.

$$x^{3\left(-1\right)}\times \frac{1}{y}$$

Multiply 3 times -1.

$$\frac{1}{x^{3}}\times \frac{1}{y}$$

Differentiate w.r.t. x

$$-\frac{3}{yx^{4}}$$