Solve (x^2-5)=12(y+8)

$$( x ^ { 2 } - 5 ) = 12 ( y + 8 )$$

Solve for y

$$y=\frac{x^{2}-101}{12}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 12 by y+8.

$$x^{2}-5=12y+96$$

Swap sides so that all variable terms are on the left hand side.

$$12y+96=x^{2}-5$$

Subtract 96 from both sides.

$$12y=x^{2}-5-96$$

Subtract 96 from -5 to get -101.

$$12y=x^{2}-101$$

Divide both sides by 12.

$$\frac{12y}{12}=\frac{x^{2}-101}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$y=\frac{x^{2}-101}{12}$$

Solve for x (complex solution)

$$x=-\sqrt{12y+101}$$

$$x=\sqrt{12y+101}$$

Solve for x

$$x=\sqrt{12y+101}$$

$$x=-\sqrt{12y+101}\text{, }y\geq -\frac{101}{12}$$