Solve (x^2-3-1)^2

$$( x ^ { 2 } - 3 - 1 ) ^ { 2 }$$

Evaluate

$$\left(x^{2}-4\right)^{2}$$

Solution Steps

Subtract 1 from -3 to get -4.

$$\left(x^{2}-4\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x^{2}-4\right)^{2}.

$$\left(x^{2}\right)^{2}-8x^{2}+16$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$x^{4}-8x^{2}+16$$

Expand

$$x^{4}-8x^{2}+16$$

Solution Steps

Subtract 1 from -3 to get -4.

$$\left(x^{2}-4\right)^{2}$$

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x^{2}-4\right)^{2}.

$$\left(x^{2}\right)^{2}-8x^{2}+16$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$x^{4}-8x^{2}+16$$