Solve (x+y+z)-10=(z+3)*z

$$( x + y + z ) - 10 = ( z + 3 ) \cdot z$$

Solve for x

$$x=10+2z+z^{2}-y$$

Solution Steps

Use the distributive property to multiply z+3 by z.

$$x+y+z-10=z^{2}+3z$$

Subtract y from both sides.

$$x+z-10=z^{2}+3z-y$$

Subtract z from both sides.

$$x-10=z^{2}+3z-y-z$$

Combine 3z and -z to get 2z.

$$x-10=z^{2}+2z-y$$

Add 10 to both sides.

$$x=z^{2}+2z-y+10$$

Solve for y

$$y=10+2z+z^{2}-x$$

Solution Steps

Use the distributive property to multiply z+3 by z.

$$x+y+z-10=z^{2}+3z$$

Subtract x from both sides.

$$y+z-10=z^{2}+3z-x$$

Subtract z from both sides.

$$y-10=z^{2}+3z-x-z$$

Combine 3z and -z to get 2z.

$$y-10=z^{2}+2z-x$$

Add 10 to both sides.

$$y=z^{2}+2z-x+10$$