Solve (x+a)^2+c+x^2+12x+4

$$( x + a ) ^ { 2 } + c + x ^ { 2 } + 12 x + 4$$

Evaluate

$$\left(x+a\right)^{2}+x^{2}+c+12x+4$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(x+a\right)^{2}.

$$x^{2}+2xa+a^{2}+c+x^{2}+12x+4$$

Combine x^{2} and x^{2} to get 2x^{2}.

$$2x^{2}+2xa+a^{2}+c+12x+4$$

Expand

$$2x^{2}+2ax+12x+a^{2}+c+4$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(x+a\right)^{2}.

$$x^{2}+2xa+a^{2}+c+x^{2}+12x+4$$

Combine x^{2} and x^{2} to get 2x^{2}.

$$2x^{2}+2xa+a^{2}+c+12x+4$$