Solve (x+8)^2=x^2+96

$$( x + 8 ) ^ { 2 } = x ^ { 2 } + 96$$

Solve for x

$$x=2$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+8\right)^{2}.

$$x^{2}+16x+64=x^{2}+96$$

Subtract x^{2} from both sides.

$$x^{2}+16x+64-x^{2}=96$$

Combine x^{2} and -x^{2} to get 0.

$$16x+64=96$$

Subtract 64 from both sides.

$$16x=96-64$$

Subtract 64 from 96 to get 32.

$$16x=32$$

Divide both sides by 16.

$$x=\frac{32}{16}$$

Divide 32 by 16 to get 2.

$$x=2$$