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x^{2}+12x+36-2=\left(x-5\right)^{2}+2
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+6\right)^{2}.
x^{2}+12x+34=\left(x-5\right)^{2}+2
Subtract 2 from 36 to get 34.
x^{2}+12x+34=x^{2}-10x+25+2
Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(x-5\right)^{2}.
x^{2}+12x+34=x^{2}-10x+27
Add 25 and 2 to get 27.
x^{2}+12x+34-x^{2}=-10x+27
Subtract x^{2} from both sides.
12x+34=-10x+27
Combine x^{2} and -x^{2} to get 0.
12x+34+10x=27
Add 10x to both sides.
22x+34=27
Combine 12x and 10x to get 22x.
22x=27-34
Subtract 34 from both sides.
22x=-7
Subtract 34 from 27 to get -7.
x=\frac{-7}{22}
Divide both sides by 22.
x=-\frac{7}{22}
Fraction \frac{-7}{22} can be rewritten as -\frac{7}{22} by extracting the negative sign.