Solve (x+5^2)*42=86

$$( x + 5 ^ { 2 } ) \cdot 42 = 86$$

Solve for x

$$x = -\frac{482}{21} = -22\frac{20}{21} \approx -22.952380952$$

Steps for Solving Linear Equation

Divide both sides by 42.

$$x+5^{2}=\frac{86}{42}$$

Reduce the fraction \frac{86}{42} to lowest terms by extracting and canceling out 2.

$$x+5^{2}=\frac{43}{21}$$

Calculate 5 to the power of 2 and get 25.

$$x+25=\frac{43}{21}$$

Subtract 25 from both sides.

$$x=\frac{43}{21}-25$$

Convert 25 to fraction \frac{525}{21}.

$$x=\frac{43}{21}-\frac{525}{21}$$

Since \frac{43}{21} and \frac{525}{21} have the same denominator, subtract them by subtracting their numerators.

$$x=\frac{43-525}{21}$$

Subtract 525 from 43 to get -482.

$$x=-\frac{482}{21}$$