Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

x+4>0 x-6<0
For the product to be negative, x+4 and x-6 have to be of the opposite signs. Consider the case when x+4 is positive and x-6 is negative.
x\in \left(-4,6\right)
The solution satisfying both inequalities is x\in \left(-4,6\right).
x-6>0 x+4<0
Consider the case when x-6 is positive and x+4 is negative.
x\in \emptyset
This is false for any x.
x\in \left(-4,6\right)
The final solution is the union of the obtained solutions.