Solve (x+4)(x-3)-(x-2)(2+x)-4=0

$$( x + 4 ) ( x - 3 ) - ( x - 2 ) ( 2 + x ) - 4 = 0$$

Solve for x

$$x=12$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+4 by x-3 and combine like terms.

$$x^{2}+x-12-\left(x-2\right)\left(2+x\right)-4=0$$

Use the distributive property to multiply x-2 by 2+x and combine like terms.

$$x^{2}+x-12-\left(x^{2}-4\right)-4=0$$

To find the opposite of x^{2}-4, find the opposite of each term.

$$x^{2}+x-12-x^{2}+4-4=0$$

Combine x^{2} and -x^{2} to get 0.

$$x-12+4-4=0$$

Add -12 and 4 to get -8.

$$x-8-4=0$$

Subtract 4 from -8 to get -12.

$$x-12=0$$

Add 12 to both sides. Anything plus zero gives itself.

$$x=12$$