Solve (x+3)(y-1)=5

$$( x + 3 ) ( y - 1 ) = 5$$

Solve for x

$$x=-\frac{3y-8}{y-1}$$

$$y\neq 1$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+3 by y-1.

$$xy-x+3y-3=5$$

Subtract 3y from both sides.

$$xy-x-3=5-3y$$

Add 3 to both sides.

$$xy-x=5-3y+3$$

Add 5 and 3 to get 8.

$$xy-x=8-3y$$

Combine all terms containing x.

$$\left(y-1\right)x=8-3y$$

Divide both sides by y-1.

$$\frac{\left(y-1\right)x}{y-1}=\frac{8-3y}{y-1}$$

Dividing by y-1 undoes the multiplication by y-1.

$$x=\frac{8-3y}{y-1}$$

Solve for y

$$y=\frac{x+8}{x+3}$$

$$x\neq -3$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+3 by y-1.

$$xy-x+3y-3=5$$

Add x to both sides.

$$xy+3y-3=5+x$$

Add 3 to both sides.

$$xy+3y=5+x+3$$

Add 5 and 3 to get 8.

$$xy+3y=8+x$$

Combine all terms containing y.

$$\left(x+3\right)y=8+x$$

The equation is in standard form.

$$\left(x+3\right)y=x+8$$

Divide both sides by x+3.

$$\frac{\left(x+3\right)y}{x+3}=\frac{x+8}{x+3}$$

Dividing by x+3 undoes the multiplication by x+3.

$$y=\frac{x+8}{x+3}$$