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x^{2}-9-x\left(x+4\right)=0
Consider \left(x+3\right)\left(x-3\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 3.
x^{2}-9-\left(x^{2}+4x\right)=0
Use the distributive property to multiply x by x+4.
x^{2}-9-x^{2}-4x=0
To find the opposite of x^{2}+4x, find the opposite of each term.
-9-4x=0
Combine x^{2} and -x^{2} to get 0.
-4x=9
Add 9 to both sides. Anything plus zero gives itself.
x=\frac{9}{-4}
Divide both sides by -4.
x=-\frac{9}{4}
Fraction \frac{9}{-4} can be rewritten as -\frac{9}{4} by extracting the negative sign.