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x^{2}-9=x^{2}+x
Consider \left(x+3\right)\left(x-3\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 3.
x^{2}-9-x^{2}=x
Subtract x^{2} from both sides.
-9=x
Combine x^{2} and -x^{2} to get 0.
x=-9
Swap sides so that all variable terms are on the left hand side.