Solve (x+3)(x-2)=x+3

$$( x + 3 ) ( x - 2 ) = x + 3$$

Solve for x

$$x=-3$$

$$x=3$$

Steps by Finding Square Root

Use the distributive property to multiply x+3 by x-2 and combine like terms.

$$x^{2}+x-6=x+3$$

Subtract x from both sides.

$$x^{2}+x-6-x=3$$

Combine x and -x to get 0.

$$x^{2}-6=3$$

Add 6 to both sides.

$$x^{2}=3+6$$

Add 3 and 6 to get 9.

$$x^{2}=9$$

Take the square root of both sides of the equation.

$$x=3 x=-3$$

Steps Using the Quadratic Formula

Use the distributive property to multiply x+3 by x-2 and combine like terms.

$$x^{2}+x-6=x+3$$

Subtract x from both sides.

$$x^{2}+x-6-x=3$$

Combine x and -x to get 0.

$$x^{2}-6=3$$

Subtract 3 from both sides.

$$x^{2}-6-3=0$$

Subtract 3 from -6 to get -9.

$$x^{2}-9=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -9 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-9\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-9\right)}}{2}$$

Multiply -4 times -9.

$$x=\frac{0±\sqrt{36}}{2}$$

Take the square root of 36.

$$x=\frac{0±6}{2}$$

Now solve the equation x=\frac{0±6}{2} when ± is plus. Divide 6 by 2.

$$x=3$$

Now solve the equation x=\frac{0±6}{2} when ± is minus. Divide -6 by 2.

$$x=-3$$

The equation is now solved.

$$x=3 x=-3$$