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Solve for x (complex solution)
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x^{2}+8x+15=9
Use the distributive property to multiply x+3 by x+5 and combine like terms.
x^{2}+8x+15-9=0
Subtract 9 from both sides.
x^{2}+8x+6=0
Subtract 9 from 15 to get 6.
x=\frac{-8±\sqrt{8^{2}-4\times 6}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 8 for b, and 6 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-8±\sqrt{64-4\times 6}}{2}
Square 8.
x=\frac{-8±\sqrt{64-24}}{2}
Multiply -4 times 6.
x=\frac{-8±\sqrt{40}}{2}
Add 64 to -24.
x=\frac{-8±2\sqrt{10}}{2}
Take the square root of 40.
x=\frac{2\sqrt{10}-8}{2}
Now solve the equation x=\frac{-8±2\sqrt{10}}{2} when ± is plus. Add -8 to 2\sqrt{10}.
x=\sqrt{10}-4
Divide -8+2\sqrt{10} by 2.
x=\frac{-2\sqrt{10}-8}{2}
Now solve the equation x=\frac{-8±2\sqrt{10}}{2} when ± is minus. Subtract 2\sqrt{10} from -8.
x=-\sqrt{10}-4
Divide -8-2\sqrt{10} by 2.
x=\sqrt{10}-4 x=-\sqrt{10}-4
The equation is now solved.
x^{2}+8x+15=9
Use the distributive property to multiply x+3 by x+5 and combine like terms.
x^{2}+8x=9-15
Subtract 15 from both sides.
x^{2}+8x=-6
Subtract 15 from 9 to get -6.
x^{2}+8x+4^{2}=-6+4^{2}
Divide 8, the coefficient of the x term, by 2 to get 4. Then add the square of 4 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+8x+16=-6+16
Square 4.
x^{2}+8x+16=10
Add -6 to 16.
\left(x+4\right)^{2}=10
Factor x^{2}+8x+16. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+4\right)^{2}}=\sqrt{10}
Take the square root of both sides of the equation.
x+4=\sqrt{10} x+4=-\sqrt{10}
Simplify.
x=\sqrt{10}-4 x=-\sqrt{10}-4
Subtract 4 from both sides of the equation.
x^{2}+8x+15=9
Use the distributive property to multiply x+3 by x+5 and combine like terms.
x^{2}+8x+15-9=0
Subtract 9 from both sides.
x^{2}+8x+6=0
Subtract 9 from 15 to get 6.
x=\frac{-8±\sqrt{8^{2}-4\times 6}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 8 for b, and 6 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-8±\sqrt{64-4\times 6}}{2}
Square 8.
x=\frac{-8±\sqrt{64-24}}{2}
Multiply -4 times 6.
x=\frac{-8±\sqrt{40}}{2}
Add 64 to -24.
x=\frac{-8±2\sqrt{10}}{2}
Take the square root of 40.
x=\frac{2\sqrt{10}-8}{2}
Now solve the equation x=\frac{-8±2\sqrt{10}}{2} when ± is plus. Add -8 to 2\sqrt{10}.
x=\sqrt{10}-4
Divide -8+2\sqrt{10} by 2.
x=\frac{-2\sqrt{10}-8}{2}
Now solve the equation x=\frac{-8±2\sqrt{10}}{2} when ± is minus. Subtract 2\sqrt{10} from -8.
x=-\sqrt{10}-4
Divide -8-2\sqrt{10} by 2.
x=\sqrt{10}-4 x=-\sqrt{10}-4
The equation is now solved.
x^{2}+8x+15=9
Use the distributive property to multiply x+3 by x+5 and combine like terms.
x^{2}+8x=9-15
Subtract 15 from both sides.
x^{2}+8x=-6
Subtract 15 from 9 to get -6.
x^{2}+8x+4^{2}=-6+4^{2}
Divide 8, the coefficient of the x term, by 2 to get 4. Then add the square of 4 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+8x+16=-6+16
Square 4.
x^{2}+8x+16=10
Add -6 to 16.
\left(x+4\right)^{2}=10
Factor x^{2}+8x+16. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+4\right)^{2}}=\sqrt{10}
Take the square root of both sides of the equation.
x+4=\sqrt{10} x+4=-\sqrt{10}
Simplify.
x=\sqrt{10}-4 x=-\sqrt{10}-4
Subtract 4 from both sides of the equation.