Solve for x
x = -\frac{3}{2} = -1\frac{1}{2} = -1.5
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x^{2}+6x+9-x^{2}=0
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
6x+9=0
Combine x^{2} and -x^{2} to get 0.
6x=-9
Subtract 9 from both sides. Anything subtracted from zero gives its negation.
x=\frac{-9}{6}
Divide both sides by 6.
x=-\frac{3}{2}
Reduce the fraction \frac{-9}{6} to lowest terms by extracting and canceling out 3.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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y = 3x + 4
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
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