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x^{2}+6x+9-9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
x^{2}+6x
Subtract 9 from 9 to get 0.
x^{2}+6x+9-9
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+3\right)^{2}.
x^{2}+6x
Subtract 9 from 9 to get 0.