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x^{2}-4+3x^{2}=\left(2x+1\right)^{2}+2x
Consider \left(x+2\right)\left(x-2\right). Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}. Square 2.
4x^{2}-4=\left(2x+1\right)^{2}+2x
Combine x^{2} and 3x^{2} to get 4x^{2}.
4x^{2}-4=4x^{2}+4x+1+2x
Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(2x+1\right)^{2}.
4x^{2}-4=4x^{2}+6x+1
Combine 4x and 2x to get 6x.
4x^{2}-4-4x^{2}=6x+1
Subtract 4x^{2} from both sides.
-4=6x+1
Combine 4x^{2} and -4x^{2} to get 0.
6x+1=-4
Swap sides so that all variable terms are on the left hand side.
6x=-4-1
Subtract 1 from both sides.
6x=-5
Subtract 1 from -4 to get -5.
x=\frac{-5}{6}
Divide both sides by 6.
x=-\frac{5}{6}
Fraction \frac{-5}{6} can be rewritten as -\frac{5}{6} by extracting the negative sign.