Solve (x+2)(x-0)(x-5)

$$( x + 2 ) ( x - 0 ) ( x - 5 )$$

Evaluate

$$x\left(x-5\right)\left(x+2\right)$$

Solution Steps

Use the distributive property to multiply x+2 by x-0.

$$\left(x\left(x-0\right)+2\left(x-0\right)\right)\left(x-5\right)$$

Apply the distributive property by multiplying each term of x\left(x-0\right)+2\left(x-0\right) by each term of x-5.

$$\left(x-0\right)x^{2}-5x\left(x-0\right)+2\left(x-0\right)x-10\left(x-0\right)$$

Combine -5x\left(x-0\right) and 2\left(x-0\right)x to get -3x\left(x-0\right).

$$\left(x-0\right)x^{2}-3x\left(x-0\right)-10\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$\left(x+0\right)x^{2}-3x\left(x-0\right)-10\left(x-0\right)$$

Anything plus zero gives itself.

$$xx^{2}-3x\left(x-0\right)-10\left(x-0\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$x^{3}-3x\left(x-0\right)-10\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$x^{3}-3xx-10\left(x-0\right)$$

Multiply x and x to get x^{2}.

$$x^{3}-3x^{2}-10\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$x^{3}-3x^{2}-10x$$

Expand

$$x^{3}-3x^{2}-10x$$

Solution Steps

Use the distributive property to multiply x+2 by x-0.

$$\left(x\left(x-0\right)+2\left(x-0\right)\right)\left(x-5\right)$$

Apply the distributive property by multiplying each term of x\left(x-0\right)+2\left(x-0\right) by each term of x-5.

$$\left(x-0\right)x^{2}-5x\left(x-0\right)+2\left(x-0\right)x-10\left(x-0\right)$$

Combine -5x\left(x-0\right) and 2\left(x-0\right)x to get -3x\left(x-0\right).

$$\left(x-0\right)x^{2}-3x\left(x-0\right)-10\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$\left(x+0\right)x^{2}-3x\left(x-0\right)-10\left(x-0\right)$$

Anything plus zero gives itself.

$$xx^{2}-3x\left(x-0\right)-10\left(x-0\right)$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$x^{3}-3x\left(x-0\right)-10\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$x^{3}-3xx-10\left(x-0\right)$$

Multiply x and x to get x^{2}.

$$x^{3}-3x^{2}-10\left(x-0\right)$$

Multiply -1 and 0 to get 0.

$$x^{3}-3x^{2}-10x$$