Solve (x+2)^2-4x=x^2+3x-1=

$$( x + 2 ) ^ { 2 } - 4 x = x ^ { 2 } + 3 x - 1 =$$

Solve for x

$$x = \frac{5}{3} = 1\frac{2}{3} \approx 1.666666667$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.

$$x^{2}+4x+4-4x=x^{2}+3x-1$$

Combine 4x and -4x to get 0.

$$x^{2}+4=x^{2}+3x-1$$

Subtract x^{2} from both sides.

$$x^{2}+4-x^{2}=3x-1$$

Combine x^{2} and -x^{2} to get 0.

$$4=3x-1$$

Swap sides so that all variable terms are on the left hand side.

$$3x-1=4$$

Add 1 to both sides.

$$3x=4+1$$

Add 4 and 1 to get 5.

$$3x=5$$

Divide both sides by 3.

$$x=\frac{5}{3}$$