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\left(x+2\right)^{2}-3+3=3
Add 3 to both sides of the equation.
\left(x+2\right)^{2}=3
Subtracting 3 from itself leaves 0.
x+2=\sqrt{3} x+2=-\sqrt{3}
Take the square root of both sides of the equation.
x+2-2=\sqrt{3}-2 x+2-2=-\sqrt{3}-2
Subtract 2 from both sides of the equation.
x=\sqrt{3}-2 x=-\sqrt{3}-2
Subtracting 2 from itself leaves 0.