Solve (x+2)^2-(x+2)^2=

$$( x + 2 ) ^ { 2 } - ( x + 2 ) ^ { 2 } =$$

Evaluate

$$0$$

Solution Steps

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.

$$x^{2}+4x+4-\left(x+2\right)^{2}$$

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.

$$x^{2}+4x+4-\left(x^{2}+4x+4\right)$$

To find the opposite of x^{2}+4x+4, find the opposite of each term.

$$x^{2}+4x+4-x^{2}-4x-4$$

Combine x^{2} and -x^{2} to get 0.

$$4x+4-4x-4$$

Combine 4x and -4x to get 0.

$$4-4$$

Subtract 4 from 4 to get 0.

$$0$$

Factor

$$0$$

Solution Steps

Factor out \left(x+2\right)^{2}.

$$0$$