Solve (x+2)^2=x^2+4^2

$$( x + 2 ) ^ { 2 } = x ^ { 2 } + 4 ^ { 2 }$$

Solve for x

$$x=3$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.

$$x^{2}+4x+4=x^{2}+4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$x^{2}+4x+4=x^{2}+16$$

Subtract x^{2} from both sides.

$$x^{2}+4x+4-x^{2}=16$$

Combine x^{2} and -x^{2} to get 0.

$$4x+4=16$$

Subtract 4 from both sides.

$$4x=16-4$$

Subtract 4 from 16 to get 12.

$$4x=12$$

Divide both sides by 4.

$$x=\frac{12}{4}$$

Divide 12 by 4 to get 3.

$$x=3$$