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Solve for x (complex solution)
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\left(x+2\right)^{2}=-16
Subtracting 16 from itself leaves 0.
x+2=4i x+2=-4i
Take the square root of both sides of the equation.
x+2-2=4i-2 x+2-2=-4i-2
Subtract 2 from both sides of the equation.
x=4i-2 x=-4i-2
Subtracting 2 from itself leaves 0.
x=-2+4i
Subtract 2 from 4i.
x=-2-4i
Subtract 2 from -4i.
x=-2+4i x=-2-4i
The equation is now solved.